If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2+28x+17=0
a = 2; b = 28; c = +17;
Δ = b2-4ac
Δ = 282-4·2·17
Δ = 648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{648}=\sqrt{324*2}=\sqrt{324}*\sqrt{2}=18\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-18\sqrt{2}}{2*2}=\frac{-28-18\sqrt{2}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+18\sqrt{2}}{2*2}=\frac{-28+18\sqrt{2}}{4} $
| (x-34)/x=60/100 | | 2/7k-3/8=13/8 | | F(x)=4x^2-10x+3 | | (x-28)/x=67/100 | | -4.9t^2+5t+1.1=0 | | 6/11(x+5)=-6 | | (x-11)/x=87/100 | | 8(-2+2v)=-128 | | 21.8-g=11.6 | | 4(x-4)+17=3(x+30) | | y=(-4)(-4)+2(-4)-7 | | z-47=38 | | 4(x-4)+17=3(x+30 | | 6-(3w+5)=7-w | | 2q^2+3q−4=0 | | y=(-5)(-5)+2(-5)-7 | | (x-10)/x=88/100 | | 6x+7=4x+55 | | .5(h-1)(h)=15 | | y=(-4)(-4)+4(-4) | | y=(-3)(-3)+4(-3) | | 40=-10x-80 | | k/8=2 | | 7x^2-14x-245=0 | | -19x-1=-12x+24 | | y=(-2)(-2)+4(-2) | | 600x-15+15=15 | | 3-0.4x=-0.4x+3 | | y=(-1)(-1)+4(-1) | | v-27=91 | | -129=7-8x | | 12-11a=45+12 |